q: (it, items 1 of items 1 of (it,(size of it, name of it) of (files of folder "d:/new
folder")) whose (item 0 of it = item 0 of item 1 of it)) of elements of set of items 0 of (size of it, name of it) of (files of folder "d:/new
folder")
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T: 253.721 ms
EXPLANATION
* 'elements of set of items 0 of
(size of it, name of it) of (files of folder "d:/new folder")'
gives the sorted values of sizes of 'files of folder 'new folder''
*'(it, items 1 of items 1 of (it,(size of it, name of it) of (files of
folder "d:/new folder"))whose (item 0 of it = item 0 of item 1 of
it))'
-In this the first & the second 'it' refers to the sorted values of
files of 'new folder'.
-'items 1 of items 1 of (it,(size of it, name of it) of (files of folder
"d:/new folder"))', refers to the names of files of 'new folder'
-if we consider the whole statement, i.e, '(it, items 1 of items 1 of
(it,(size of it, name of it) of (files of folder "d:/new
folder"))whose (item 0 of it = item 0 of item 1 of it))', a whose
statement is added at the end in which
the 'item 0 of it' is referring to the second 'it' of the statement, which in
turn refers to the sorted values of sizes of files of 'new folder', and 'item 0
of item 1 of it' is referring to the unsorted values of files of folder 'new
folder'.
on the whole the sizes are bieng compared and the names of those files
are displayed, whose sizes matches the sorted order of sizes of files of 'new
folder' along with their sizes.